Got the ans thanks neede coz i had doubt but got clarified

i. 170 m

ii. 850 m

Explanation:

Question

Arjun and his son Arav were standing ‘x’ m away from each other. They are equidistant (Y m) from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculate

i. the distance between Arjun and Arav

ii. the distance between the cliff and Arjun

The parameters given are;

The time for the sound to reach Arav, = 0.5 s

Time for the echo to echo to reach Arav, = 2 s

The distance between Arjun and Arav =

The distance between Arav and the cliff =

The speed of sound in air, s = 340 m/s

The formula for speed, s, is , therefore;

= 0.5 s × 340 m/s = 170 m

The distance between Arjun and Arav = 170 m

ii. Since Arav hears the direct sound before the echo, he is closer to the cliff than Arjun, therefore, we have;

= 2 s × 340 m/s = 680 m

Therefore, the distance between Arav and the cliff = 680 m

Which gives the distance between the cliff and Arjun, = The distance between Arav and the cliff + The distance between Arjun and Arav

= 680 + 170 = 850 m.

b mirrors submit a iisner? e. for which optical devices does d sometimes have a positive value? o a a and b o b. a and c o c. b and d 0 d. b and cb

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.