Dos poleas de diferentes tamaños se encuentran unidas por medio de una correa que no desliza. Los radios deblas poleas son de 30cm y 10cm. La polea mayor se encuentra unida a través de su centro con un motor que se encuentra girando con una velocidad angular de 8π rad/s. Determine: 1) La velocidad lineal (tangencial) de la polea 1 2) La velocidad angular que tendrá la polea 2 3) El radio que tendría que tener otra polea (3) unida a la polea menor por medio de otra correa para que esta gire con una velocidad angular de 2π rad/s

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Ithink it’s: light bounce if off a mirror

Answer mechanical energy;