Two small conducting point charges, separated by 0.5 m, carry a total charge of 170 mu or micro CC. They repel one another with a force of 120 N. For the universal constant k use the value 8.99 times 109 N m2/C2. Find the charge on the larger of the two point charges.

the two point charges are equal

q₁ = 147.353 x 10⁻⁶ C or 22.646 x 10⁻⁶ C

q₂ =  22.647 x 10⁻⁶ C  or 147.354 x 10⁻⁶ C

Explanation:

Given;

distance between the two charges, r =  0.5 m

let the first charge = q₁

let the second charge = q₂

q₁ + q₂ = 170μ = 170 x 10⁻⁶ C ---------- equation (1)

Force of repulsion between the two charges, q₁ and q₂ = 120 N

Coulomb's constant, K =  8.99 x 10⁹ N m²/C²

Apply coulomb's law, for force of attraction or repulsion between two point charges;

--------------  equation (2)

From equation (1); q₂ = 170 x 10⁻⁶ C  - q₁

Substitute in the value of q₂ in equation (2)

q₁(170 x 10⁻⁶  - q₁) = 3.337 x 10⁻⁹

170 x 10⁻⁶q₁ - q₁² = 3.337 x 10⁻⁹

170 x 10⁻⁶q₁ = q₁² + 3.337 x 10⁻⁹

0 = q₁² - 170 x 10⁻⁶q₁ + 3.337 x 10⁻⁹ (this is quadratic equation)

q₁ = 147.353 x 10⁻⁶ C or 22.646 x 10⁻⁶ C

q₂ = 170 x 10⁻⁶ C  - q₁

q₂ = 170 x 10⁻⁶ C - 147.353 x 10⁻⁶ C     or    170 x 10⁻⁶ C -  22.646 x 10⁻⁶ C

q₂ =  22.647 x 10⁻⁶ C  or 147.354 x 10⁻⁶ C

Therefore, the two point charges are equal

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!