In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg, collide. Bicycle 1 was moving to the right at 5 m/s, while Bicycle 2 was
moving to the left at 3 m/s. What is the magnitude of their combined
momentum before the crash?

20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

V1 = 5 m/s , V2 = 3 m/s

Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

momentum before the crash will be:

M1V1 - M2V2

Substitute all the parameters into the formula

10 × 5 - 10 × 3

50 - 30

20 kgm/s

Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

we need to know the time interval during which the force acts. impulse of force = momentum change

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation