A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The free body diagram is shown. What is the net force in the x-direction?

34.4N

Explanation:

Given the following :

Applied force (F) = 65N

Angle of inclination (Θ) = 58°

g = acceleration due to gravity = 9.8m/s^2

Therefore, net force in the x-direction is given has;

The horizontal component of force;

Fx = mgCosΘ

Fhorizontal = mass × acceleration due to gravity × cosΘ

mass × acceleration due to gravity = 65N

Fx = 65N × Cos58°

Fx = 65 × 0.5299192

Fx = 34.44N

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