An uniform electric field of magnitude E = 100 N/C is oriented along the positive y-axis. What is the magnitude of the flux of this field through a square of surface area A = 2 m2 oriented parallel to the yz-plane? Group of answer choices

∅ = 0 V.m

Explanation:

The electric flux through a surface is given by the following formula:

∅ = E.ΔA

∅ = E ΔA Cosθ

where,

∅ = Electric Flux through the surface = ?

E = Electric Field Intensity = 100 N/C

ΔΑ = Surface Area = 2 m²

θ = Angle between the electric field and the the normal area vector

The electric field is oriented in positive y-axis direction. The surface is parallel to yz-plane, so its normal area vector will be in the direction of x-axis. Therefore, the electric field and normal area vector shall be perpendicular to each other. Therefore,

θ = 90°

Using values in the equation:

∅ = (100 N/C)(2 m²)(Cos 90°)

∅ = (200 N.m²/C)(0)

∅ = 0 V.m

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)