What is the spring constant of a bungee cord that stretches and additional 55 m 6000 N of force are playing

K = 109.1 N/m

Explanation:

From the question, the following parameters are given.

Extension e = 55 m

Force F = 6000N

According to Hooke's law,

F = Ke

Where K = spring constant.

Substitute F and e into the formula and make K the subject of formula.

6000 = K × 55

K = 6000/55

K = 109.1 N/m

Therefore, the spring constant of a bungee cord that stretches is 109.1 N/m

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.