A schooterist move along a circular path for radius 0.2km for 2 minutes A ) what is the distance travelled
B) what is the velocity of the schooterist

a 1.26 km b 10.5 m/s

Explanation:

A. Distance travelled by the schooterist

Since the schooterist travels in a circular path, the distance moved is the circumference of a circle, C with radius r = 0.2 km

C = 2πr

= 2π(0.2 km)

= 1.26 km

So, the distance travelled by the schooterist is 1.26 km

B. The velocity of the schooterist

The velocity of the schooterist v = distance travelled/time

distance travelled = 1.26 km = 1260 m

time = 2 minutes = 2 × 60 s = 120 s

So, V = 1260 m/120 s

= 10.5 m/s

So, the velocity of the schooterist is 10.5 m/s

28. evolution

29. environment, survive, offspring  

explanation:

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