A parallel-plate capacitor is charged by a 14.0 V battery, then the battery is removed. You may want to review (Pages 692 - 695) . Part A What is the potential difference between the plates after the battery is disconnected

Potential Difference = 14 V

Explanation:

We are told that when the capacitor plates are charged to a certain voltage, then we have;

ΔV = 14 volts

Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;

ΔV = Q/C

Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.

Thus;

Potential Difference = 14 V

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