Suppose the Helmholtz coil in this experiment is arranged to produce a magnetic field that points east. The current through the coils is 11.5 mA. With the current off, the red needle of the compass points at zero degrees on the compass' bezel. At what angle will the compass needle rotate through when current is turned on and left on for a several seconds? Assume the horizontal component of the Earth's magnetic field is 0.24 G and recall the constant k = 17.0 G/A.

∅ = 39.2°

Explanation:

B= Bhorizontal × tan ∅

11.5×10⁻³ × 17 = 0.24 tan ∅

tan ∅ = (11.5×10⁻³× 17) ÷ 0.24

tan ∅ = 0.8146

∅ = tan⁻¹ 0.8146

∅ = 39.2°

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

explanation:

wheres the pic