Calculate the isochore molar heat capacity of a distiomkc has knowing the molecules mean square velocity of Vr=600m/s at T=27C

Therefore the isochore polar heat capacity of a diatomic is 20. 785 J/mol K

Explanation:

Solution

Recall that:

Vr = 600 m/s

T = 27°C

The molar heat capacity at constant volume is given below:

Cv = R/r -1

Here

r = 1 +2/f

For diatomic f = 5

Thus

r =1 +2/f =7/5

v =R/7/5 - 1

=5R/2 =5/2 * 8.314 J/mol K

Hence Cv = 20. 785 J/mol K

the answer to this question is 60 n

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s