A gymnast of mass 66.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity. Part A: Calculate the tension T in the rope if the gymnast hangs motionless on the rope.
Express your answer in newtons.
Part B: Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.
Express your answer in newtons.
Part C: Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 1.50 m/s2 .
Express your answer in newtons.
Part D: Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 1.50 m/s2 .
Express your answer in newtons.

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

120v is the answer i am positive tell me if this was correct