A 10 kg body is suspended by a rope is pulled by means of a horizontal force to make 60°
by rope to vertical. The horizontal force is
1) 10 kgwt
2) 30 kgwt
3) 10/3 kgwt 4) 30/3 kgwt

The correct option is;

3) 10·√3 kgwt

Explanation:

The parameters given are;

Mass of body, m = 10 kg

Direction of applied force = Horizontal

Angle of inclination of the rope with the vertical, θ = 60°

The component of the tension in the rope equivalent to the force is given by the relation;

T·sin(θ) = F

The component of the rope tension still under gravitational pull  is given by the relation;

T·cos(θ) = m·g

Therefore, we have;

Which gives;

Therefore;

F = tan(θ) × m×g

Where:

g = Acceleration due to gravity

tan(θ) = √3

m = 10 kg

∴ F = 10·√3 × g = 10·√3 kg-wt.

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explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.