If It took 40 Seconds for a vehicle of weight 40,000 Newton to move round a 7 metres, What time will it achieve same feat for another circular path Of radius 21 metres given the Condition of the vehicle remains the same.

  t = 376.99 s

Explanation:

We must solve this problem with the equations and kinematics, let's start by looking for the speed of the vehicle,

         v = d / t

         v = 7/40

         v = 0.175 m / s

Since the speed e remains constant, we must find the length of the circle is

          L = 2π r

          L = 2π 21

          L = 131.95 m

In the problem it does not specify clearly, but in general the curves of the road correspond to half a circle, so the length of the road is

         L ’= L / 2

         L ’= 131.95 / 2 = 65.97 m

as the speed is constant

          t = L ’/ v

          t = 65.97 / 0.175

          t = 376.99 s

i would say