The temperature of 20 liters of helium gas is increased from 100°K to 300°K. If the pressure was kept constant, the new volume will be how many liters? a) 6.7 b) 30 c) 60 d) 120 e) None of these

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

hey , the answer is c

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