What is the velocity of a 900-kg car initially moving at 30.0 m/s, just after it hits a 150-kg deer initially running at 18.0 m/s in the same direction

What is the velocity of a 900-kg car initially moving at 30.0 m/s, just after it hits a 150-kg deer initially running at 18.0 m/s in the same direction? Assume the deer remains on the car.

28.29m/s

In this situation, linear momentum is conserved. And since the deer remains on the car after collision, the linear momentum is given as;

( x ) + ( x ) = ( + ) v            -----------------(i)

Where;

= mass of car

= initial velocity of car before collision

= mass of deer

= initial velocity of the deer before collision

v = common velocity with which the car and the deer move after collision

From the question;

= 900kg

= +30.0m/s    (direction of the motion of the car taken positive)

= 150kg

= +18.0m/s    (relative to the direction of the car, the velocity of the deer is also positive )

Substitute these values into equation (i) as follows;

(900 x 30.0) + (150 x 18.0) = (900 + 150)v

27000 + 2700 = 1050v

29700 = 1050v

v =

v = 28.29m/s

Therefore, the velocity of the car after hitting the deer is 28.29m/s. This is also the velocity of the deer after being hit by the car.

pe = weightxheight = 2000x1000=2,000,000joules

increases it