Physics, 13.07.2020 20:01 duartealondra45

A piece of tape is pulled from a spool and lowered toward a 100-mg scrap of paper. Only when the tape comes within 8.0 mm is the electric force magnitude great enough to overcome the gravitational force exerted by Earth on the scrap and lift it. Requried:
Determine the magnitude and direction of the electric force exerted by the tape on the paper at this distance.

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Answer from: KKHeffner02

The magnitude of the electric force is $F_e = 0.00098 \ N$

Explanation:

From the question we are told that

The mass of the paper is $m= 100 mg = 100 *10^{-6} \ kg$

The position is $d = 8.0\ mm = 0.008 \ m$

Generally the magnitude of the electric force at the point of equilibrium between the electric force and the gravitational force is mathematically represented as

F_e = F_g = mg

Where F_g is gravitational force

substituting values

$F_e = 100 *10^{-6} * 9.8$

$F_e = 0.00098 \ N$

Now generally the gravitational force acts downward (negative y axis ) hence the reason the electric force is same magnitude but opposite in direction (upward + y - axis )

Answer from: Quest

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Answer from: Quest

the force on the thing and the distance the force moves the thing

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A piece of tape is pulled from a spool and lowered toward a 100-mg scrap of paper. Only when the tap...

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