PLS HELP ILL MARK U BRAINLIEST I DONT HAVE MUCH TIME!! A football player of mass 103 kg running with a velocity of 2.0 m/s [E] collides head-
on with a 110 kg player on the opposing team travelling with a velocity of 3.2 m/s
[W]. Immediately after the collision the two players move in the same direction.
Calculate the final velocity of the two players.

The final velocity of the two players is 0.69 m/s in the direction of the opposing player.

Explanation:

Since the players are moving in opposite directions, from the principle of conservation of linear momentum;

- = v

Where: is the mass of the first player, is the initial velocity of the first player, is the mass of the second player, is the initial velocity of the second player and v is the final common velocity of the two players after collision.

= 103 kg, = 2.0 m/s, = 110 kg, = 3.2 m/s. Thus;

103 × 2.0 - 110 × 3.2 = (103 + 110)v

206 - 352 = 213 v

-146 = 213 v

v =

v = -0.69 m/s

The final velocity of the two players is 0.69 m/s in the direction of the opposing player.

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.