A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.

14.4 m

The distance covered by the body is 14.4 m.

Solution,

Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.

Acceleration (a)= 0.2 m/s

Time (t):

Now,

Applying third equations of motion:

Thus, the distance covered by the body is 14.4 metre.

Further more information:

Application of equation of motion in different situation:When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/sWhen a moving object comes in rest,in the case, final velocity(v)= 0 m/sIf the object is moving with uniform velocity, in the case, (u=v)If any object is thrown vertically upward, in the case, acceleration (a)= -gWhen an object is falling from certain height, in the case, u= 0 m/sWhen an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.

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