An electron moving with a velocity of 5 × 104 m s -1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s -2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this tim

(i)    t = 5s

(ii)    x = 3.75*10^5 m

Explanation:

(i) To calculate the time that the electron takes to reach twice the value of its initial velocity, you use the following formula:

        (1)

vo: initial velocity of the electron = 5*10^4 m/s

v: final velocity of the electron = 2vo = 1*10^5 m/s

a: acceleration of the electron = 1*10^4 m/s^2

You solve the equation (1) for t, and replace the values of the parameters:

The electron takes 5s to reach twice its initial velocity.

(ii) The distance traveled by the electron in such a time is:

         (2)

you replace the values of the parameters in the equation (2):

The distance traveled by the electron is 3.75*10^3m/s

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

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