Find the depth of water at which an air of radius 0.003m bubble may remain in equilibrium (surface tension=0.072Nm, gravity=9.8gs²)

h = 0.047 m

Explanation:

It is given that,

Radius of an air bubble is 0.0003 m

The surface tension of water is

We need to find the depth at which an air bubble of radius 0.0003 m will  remain in equilibrium in water. Let it is given by h.

Pressure due to surface tension is given by :

.....(1)

T is surface tension

Also, pressure due to a height is given by :

So, equation (1) becomes :

So,

So, the depth is 0.047 m.

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