a bird experiences an acceleration of -1.80m/s^2 for 3.81 s and ends up 26.5 m to the left of its starting point. what is its final velocity?

For a questions which involves constant acceleration, you can use the SUVAT equations.

S - displacement - -26.5m ( If you to take the right as a positive value - since displacement is a vector quantity involving direction and magnitude)

U

V - Final Velocity - unknown

A - Acceleration - -1.8m/s^2

T - Time - 3.81s

s = vt - 1/2at^2

-26.5m = 3.81v - 1/2 • -1.8 • 3.81^2

Rearrange

-26.5m/-1/2•-1.8•3.81^2=3.81v

3.81v = -2.028~

v = -0.532~ (3sf)

My answer is opptionc, just check with anyone else