WILL GIVE BRANLIET PLS HELP I REALLY COULD USE THE HELP Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. Do this using three different methods. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance between the slits is 0.000250 m.

λ = 6,108 10⁻⁷ m = 610.8 nm

λ = 5.513 10⁻⁷ m = 551.3 nm

Explanation:

Young's double slit experiment results in a pattern consisting of maxima and minima of interference, the maximums are described by the expression

          d sin θ = m λ

where d of the distance between the two slits, θ is the angle from the central maximum to the given interference line, λ the wavelength of the radiation and an integer indicating the order of interference

In this exercise they give us several conditions

The first

the angle is 1.12º to the maximum m = 8

the distance between the slits d = 0.000250 m

of the initial equation

           λ = d sin θ / m

           λ = 0.000250 sin 1.12 / 8

           λ = 6,108 10⁻⁷ m = 610.8 nm

The second

the distance from the slits to the screen is L = 302.0 cm = 3.020 m

the distance from the central maximum is y = 3.33 cm = 0.0333 m for interference m = 5

in this case we use that the angle in the experiment is small

      tan θ = y / L

      tan θ = sin θ / cos θ = sin θ

we substitute

       sin θ = y / L

       d y / L = m λ

       λ = d y / L m

we calculate

       λ = 0.000250 0.0333 / (3,020 5)

       λ = 5.513 10⁻⁷ m = 551.3 nm

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