a perfect carnot engine operates between the temperatures of 300 k and 700 k, drawing 60 kj of heat from the 700 k reservoir in each cycle. How much heat is dumped into the 300 k reservoir in each cycle

25.712 kJ

Explanation:

Given that

Initial temperature, T(i) = 300 K

Final temperature, T(f) = 700 K

Heat of the final temperature, Q(f) = 60 kJ

Heat of the initial temperature, Q(i) = ?

Now, we use the relation to solve the question

1 - (T(l)/T(h) = k(max)

1 - (300 / 700) = k(max)

1 - 0.4286 = k(max)

k(max) = 0.5714

Also, k(max) can be used in the relationship

k(max) = W / Q(f)

0.5714 = W / Q(f)

0.5714 * 60 = W

W = 34.284 kJ

Q(l) = 60 - 34.284

Q(l) = 25.716 kJ

Thus, the amount of heat pumped into the 300 K reservoir, is 25.72 kJ

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .

area of focus