Consider two soap bubbles with radius r1 and r2 (r1 <r2) connected via a valve. What happens if we open the valve

Complete Question

The  complete question is shown on the first uploaded image

The pressure difference of the first bubble is  

The pressure difference of the second bubble is  

The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger

Explanation:

From the question we are told that

    The  radius of the first bubble is  

      The radius of the second bubble is  

      The surface tension of the soap solution is  

Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as

Now the pressure difference for the first bubble is  mathematically evaluated as

substituting values  

Now the pressure difference for the second bubble is  mathematically evaluated as

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

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