A skydiver jumps out of a helicopter and falls freely for 5.6 s before opening the parachute. (a) What is the skydiver's downward velocity when the parachute opens? Correct: Your answer is correct. m/s (b) How far below the helicopter is the skydiver when the parachute opens? Incorrect: Your answer is incorrect. m

The final velocity of the skydiver when the parachute opens is 54.88 m/s.

The distance traveled by the skydiver during this time is 153.66 m.

The given parameters;

The final velocity of the skydiver when the parachute opens is calculated as follows;

The distance traveled by the skydiver during this time is calculated as follows;

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A. 54.88m/s.

B. 153.66m

Explanation:

Data obtained from the question include:

Time (t) = 5.6 secs

A. Determination of the skydiver's downward velocity.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Velocity (v) =..?

v = gt

v = 9.8 x 5.6

v = 54.88m/s

Therefore, the skydiver's downward velocity is 54.88m/s

B. Determination of the height below the helicopter.

Time (t) = 5.6 secs

Acceleration due to gravity (g) = 9.8m/s²

Height (H) =..?

H = ½gt²

H = ½ x 9.8 x 5.6²

H = 153.66m

Therefore, the height below the helicopter when the parachute opens is 153.66m.

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

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i think it's 35 meters