A rubber ball is attached to a string and whirled around in a circle. If the string is 1.0 m long (measured from the center of the baseball to the far end of the string) and the ball’s speed is 10 m/s, what is the ball’s centripetal acceleration?

Centripetal acceleration = (speed squared) / (radius)

Centripetal acceleration = (10 m/s)² / (1.0 m)

Centripetal acceleration = (100 m²/s²) / (1.0 m)

Centripetal acceleration = 100 m/s²

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm