A pushing force of 12 N is applied on a box for 32 ms. What is the magnitude of the impulse of this force?

magnitude of the impulse of this force is 0.384 Ns

Explanation:

Given the following :

Pushing force (F) = 12N

Duration of the force = time (t) = 32ms, hence, time = 32 × 10^-3 seconds

The impulse of a body is given by the product of the force and the duration of the applied force ;

Therefore impulse = F × t

Impulse = 12 (N) × (32 × 10^-3) (s)

Impulse = 384 × 10^-3

Impulse = 0.384 Ns

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