Two small, identical conducting spheres repel each other with a force of 0.030 N when they are 0.65 m apart. After a conducting wire is connected between the spheres and then removed, they repel each other with a force of 0.075 N. What is the original charge on each sphere? (Enter the magnitudes in C.)

Note that the methods applied in solving this question is the appropriate method. Check the parameters you gave in the question if you did not expect a complex number for the charges. Thanks

Explanation:

Note: When a conducting wire was connected between the spheres, the same charge will flow through the two spheres.

The two charges were 0.65 m apart. i.e. d = 0.65 m

Force, F = 0.030 N

The force or repulsion between the two charges can be calculated using the formula:

Due to the wire connected between the two spheres,

The sum of the charges on the two spheres =

Note: When the conducting wire is removed, the two spheres will no longer contain similar charges but will rather share the total charge unequally

Let charge in the first sphere =

Charge in the second sphere, q₂ =

Force, F = 0.075 N

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.