g A centripetal force F is applied to an object moving at a constant speed v in a horizontal circle of radius r. If the radius is quadrupled and the speed is doubled, what happens to the centripetal force

The centripetal force remains constant.

Explanation:

The magnitude of centripetal force is given by the following formula:

F = mv²/r

where,

F = Centripetal Force

m = mass of the object

v = velocity of the object

r = radius of the circle

Now, if we quadruple the radius (r = 4r) and the speed is doubled (v = 2v). Then the centripetal force becomes:

F' = m(2 v)²/4r

F' = (4/4)(mv²/r)

F' = mv²/r

F' = F

Thus, the centripetal force remain constant.

the answer would be a

frequency or wavelenth of em radiation in a vacuum