A spring with a spring constant of 110N/m is stretched by 12 cm. How much force is applied to the spring to stretch it

The force on the spring is 13.2 N.

The force acting on an elastic material is directly proportional to the extension of the material. This is given by Hooke's law. Mathematically, we can write; Fαe.

Introducing the constant of proportionality k;

F = ke

F = force on the spring

k = force constant

e = extension

Substituting the values we have;

F = 110N/m (0.12m)

F = 13.2 N

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force = 1320N

Explanation:

spring constant = force/extension

110 = F/12

F= 110 x 12 = 1320N

this would be about 43%

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.