A glass window of width W 1 m and height H 2 m is 5 mm thick and has a thermal conductivity of kg 1.4 W/mK. If the inner and outer surface temperatures of the glass are 15 C and 20 C, respectively, on a cold winter day, what is the rate of heat loss through the glass

Explanation:

Rate of heat conduction is given by the formula

Q = KA(T₂ -T₁ ) / L

where K is a constant called thermal conductivity , A is surface area , (T₂ -T₁ ) is temperature difference and L is thickness of glass . Q is heat conducted per unit time .

Putting the given values in the equation

Q = 1.4 x 1 x 2 x ( 20 - 15) / .005

= 2800 J per second .

Q

the maxium height is 34m/s

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