1. height of tower when stone dropped from it reaches ground in 10s is

490.5 m

Explanation:

we can use the formula s = ut + ½at^2

s= displacement (height of tower)

initial velocity u = 0 m/s

acceleration a = take 9.81 ms-2 (acceleration due to gravity, which is a constant. depending on the given instructions of the question, it may not be exactly 9.81. Some take 10, some take 9.80665)

time t =10s

s = 0t + 1/2 (9.81)(10)^2

s = 490.5 m

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

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