A train starting from rest picks up a speed of 20 m/s in 20 s while travelling on a straight path. It continues to move at the same speed for the next 50 s. It is then brought to rest in the next 10 s. a. Plot the speed-time graph for the train..

e. How much distance did the train cover during this entire journey?

Explanation:

As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from to is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.

The total distance covered by the train during the entire journey is the area of the speed-time graph.

Area

As velocity is in and time is in so the unit of area is

Hence, the total distance is  .

car a and b are moving in opposite directions

plz mark.me the brainliest i rlly need this kind of yours in exchange

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west