A rod has length 0.900 mm and mass 0.500 kgkg and is pivoted at one end. The rod is not uniform; the center of mass of the rod is not at its center but is 0.500 mm from the pivot. The period of the rod's motion as a pendulum is 1.49 ss. What is the moment of inertia of the rod around the pivot

The moment of inertia is  

Explanation:

From the question we are told that

    The length of the rod is  

     The mass of the rod is  

      The distance of the center of mass from the pivot is  

      The period of the rod's motion is  

Generally the period of the motion is mathematically represented as

Where is the moment of inertia about the pivot so making the subject of formula

substituting values

i think it would be 5