If a speed sound in air at o°c is 331m/s. what will be its value at 35 °c

352 m/s

Explanation:

The velocity of sound in air is approximated as:

v ≈ 331 + 0.6 T

where v is the velocity in m/s and T is the temperature in Celsius.

At T = 35:

v = 331 + 0.6 (35)

v = 352 m/s

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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