A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V
battery. What is the voltage drop
across the 20.0 Ohm resistor?
(Hint: How much current flows
across it?)
(Unit = V)

2.25 V

Explanation:

The equivalent resistance is:

R = 20.0 Ω + 60.0 Ω

R = 80.0 Ω

The current is:

V = IR

9.00 V = I (80.0 Ω)

I = 0.1125 A

The voltage drop across the 20.0 Ω resistor is:

V = IR

V = (0.1125 A) (20.0 Ω)

V = 2.25 V

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr