Assume a uniform cylinder rolls without slipping on a horizontal surface. Assume the cylinder has a mass of 2.0 kg and a radius 0.5 m. If during 1.0 s the center of mass undergoes 0.2 m of translation, how many meters does a point on the rim of the cylinder travel during that same time?

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

1/0.14nm = 10^10/1.4 a lot

conduction, convection, radiation

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft