A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.460 Hz. The pendulum has a mass of 2.40 kg, and the pivot is located 0.380 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point.

The  moment of inertia is  

Explanation:

From the question we are told that

    The  frequency is  

    The  mass of the pendulum is  

    The  location of the pivot from the center is

Generally the period of the simple harmonic motion is mathematically represented as

Where I is the moment of inertia about the pivot point , so making I the subject of the formula it

=>    

But the period of this simple harmonic motion can also be represented mathematically as

substituting values

So

divide the right side by the left side

0.024÷1.2=0.02 for example

1/0.14nm = 10^10/1.4 a lot