A projectile is fired from a height of 80 M above sea level, horizontally with a speed of 360 M / S, calculate: The time it takes for the projectile to reach the water. The Horizontal scope. The height that remains to descend after 2 seconds of being launched.

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

Where:

, - Initial horizontal and vertical position of the projectile, measured in meters.

, - Initial horizontal and vertical speed of the projectile, measured in meters per second.

- Time, measured in seconds.

- Gravitational acceleration, measured in meters per square second.

, - Current horizontal and vertical position of the projectile, measured in meters.

Given that , , , and , the kinematic equations are, respectively:

(a) If , the time taken for the projectile to reach the water is:

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If , the horizontal scope of the projectile is:

The horizontal scope of the projectile is 1591.2 meters.

(c) If , the height that remains to descend is:

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

pe = weightxheight = 2000x1000=2,000,000joules

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