(a) Determine the capacitance of a Teflon-filled parallel-plate capacitor having a plate area of 1.80 cm2 and a plate separation of 0.010 0 mm. pF

(b) Determine the maximum potential difference that can be applied to a Teflon-filled parallel-plate capacitor having a plate area of 1.80 cm2 and a plate separation of 0.010 0 mm.
kV

Explanation:

(a) Given that,

Area of a parallel plate capacitor,

The separation between the plates of a capacitor,

The dielectric constant of, k = 2.1

When a dielectric constant is inserted between parallel plate capacitor, the capacitance is given by :

Putting all the values we get :

(b) We know that the Teflon has dielectric strength of 60 MV/m,

The voltage difference between the plates at this critical voltage is given by :

or

V = 0.6 kV

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