A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the a. Stress of the wire.
b. Strain of the wire

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m =

Extended by = 0.25mm =

Based on the above information, the calculation is as follows

a. The Stress of the wire is

here area of circle = perpendicular to the are i.e cross-sectional  i.e

=

=

Now place these above values to the above formula

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

=

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?

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