Will mark as BRAINLIEST The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation 4x³+3x²-5x+2 , where x is in meters and t is in sec.
a)Find velocity of particle at i) t=2 sec ii) t=4 sec.
b) Find the acceleration of the particle at t=3 sec.

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

Where,

x is in meters and t is in sec

We know that,

Velocity,

(a) i. t = 2 s

At t = 4 s

(b) Acceleration,

Pu t = 3 s in above equation

So,

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

need to see circuit to get time constant

unbalanced force

explanation: