To get an idea of the order of magnitude of inductance, calculate the self-inductance in henries for a solenoid with 1500 loops of wire wound on a rod 13 cm long with radius 2 cm

The self-inductance in henries for the solenoid is 0.0274 H.

Explanation:

Given;

number of turns, N = 1500 turns

length of the solenoid, L = 13 cm = 0.13 m

radius of the wire, r = 2 cm = 0.02 m

The self-inductance in henries for a solenoid is given by;

where;

is permeability of free space =

A is the area of the solenoid = πr² = π(0.02)² = 0.00126 m²

Therefore, the self-inductance in henries for the solenoid is 0.0274 H.

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12000j is work done