Will mark as BRAINLIEST A balloon is ascending at the rate of 4.9 m/s. A packet is dropped from from the balloon when situated at a height of 100m.
How long does it take the packet to reach the ground ?
What is it's final velocity ?

initially the packet was ascending up with the balloon.

Taking upward as positive direction;

initial velocity, u = 4.9 m/s

final velocity = v m/s

initial height, h₁ = 245 m  

final height, h₂ = 0

a = -9.8 m/s²

time taken = t seconds

s = ut + 0.5at²

⇒ (h₂-h₁) = ut + 0.5at²

⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²

⇒ -245 = 4.9t - 4.9t²

⇒ 4.9t² -4.9t -245 =0

Solving it, we get  t = 7.59s

v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s

So velocity is 69.48 m/s downward

Explanation:

powerful computers now, not then

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle