A green light is submerged 2.70 m beneath the surface of a liquid with an index of refraction 1.31. What is the radius of the circle from which light escapes from the liquid into the air above the surface

The radius is  

Explanation:

From the question we are told that

        The  distance  beneath the liquid  is  

        The refractive index of the liquid is  

Now the critical value is mathematically represented as

substituting values

Using SOHCAHTOA rule we have that

=>    

substituting values  

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.