A 590-turn solenoid is 12 cm long. The current in it is 36 A . A straight wire cuts through the center of the solenoid, along a 4.5-cm diameter. This wire carries a 27-A current downward (and is connected by other wires that don't concern us). What is the magnitude of the force on this wire assuming the solenoid's field points due east?

Complete Question

A 590-turn solenoid is 12 cm long. The  current in it is 36 A . A 2 cm straight wire cuts through the center of the solenoid, along a 4.5-cm diameter. This wire carries a 27-A current downward (and is connected by other wires that don't concern us).

What is the magnitude of the force on this wire assuming the solenoid's field points due east?

The force is  

Explanation:

From the question we are told that

   The number of turns is  

   The  length of the solenoid is  

   The current is  

   The  diameter is  

   The  current carried by the wire is  

    The  length of the wire is  

Generally the magnitude of the force  on this wire assuming the solenoid's field points due east is mathematically represented as

Here  B  is the magnetic field which is mathematically represented as

Here   is permeability of free space with value  

substituting values

So

it doesn't. it was imagined up in the middle ages.