The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2

3.75m/s²

Explanation:

g= GM/r²

For planet 1

= GM/r²                   (i)

= 15m/s²

for planet 2

radius= 2*r= 2r

g= GM/r

= GM/(2r)²

= GM/4r²

=  GM/r² *1/4

from (i)

=   *1/4

= 15/4

= 3.75m/s²

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.