A liquid of density 1250 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the flow speed is 9.93 m/s and the pipe diameter d1 is 11.1 cm. At Location 2, the pipe diameter d2 is 16.7 cm. At Location 1, the pipe is Δy=8.89 m higher than it is at Location 2. Ignoring viscosity, calculate the difference ΔP between the fluid pressure at Location 2 and the fluid pressure at Location 1.

The  pressure difference is  

Explanation:

From the question we are told that

   The  density is  

   The  speed at location 1  is  

    The  diameter at location 1 is  

     The  diameter at location 2 is  

     The  height at location 1 is  

       The  height at location 2  is  

Generally the cross- sectional area at location 1 is mathematically represented as

=>    

=>    

Generally the cross- sectional area at location 2 is mathematically represented as

=>    

=>    

From continuity formula

=>    

=>      

=>      

Generally according to Bernoulli's theorem

=>  

=>

=>

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j