Light of wavelength 500 nm illuminates a round 0.50-mm-diameter hole. A screen is placed 6.0 m past the slit. What is the width of the central bright circle on the screen

14.64*10^-3 m

Explanation:

given that

Length of the wavelength, λ = 500*10^-9 m

Diameter of the hole, D = 0.5 mm

length of the slit, L = 6 m

W = 2.44 λL / D, where

W = width of the screen in m

λ = wavelength of the light in nm

L = length of the slit in m

D = diameter of the hole in m

on substituting the values, we have

W = (2.44 * 500*10^-9 * 6) / 0.5*10^-3

W = 7.32*10^-6 / 0.5*10^-3

W = 0.01464 mm

or also, 14.64*10^-3 m

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.